Rohit Sharma now has the most sixes in T20Is© AFP
Indian skipper Rohit Sharma now has the most sixes in T20I cricket history. The offensive batter accomplished this feat during his side’s second T20I against Australia in Nagpur on Friday. Rohit Sharma hit a glorious undefeated 46 out of 20 balls in the game, helping the Men in Blue achieve the goal of 91 runs in a rainy game that was reduced to eight overs per side. His innings was decorated with four limits and four sixes.
Now Rohit has a total of 176 sixes in T20I cricket. In second place is New Zealand opener Martin Guptill (172). They are followed by West Indian legend Chris Gayle (124), former England skipper Eoin Morgan (120) and Australian veteran Aaron Finch (119).
Rohit has scored 3,677 runs in 138 games in 130 innings in T20I cricket, covering four centuries and 28 half-centuries at an average of 32.53. Of these 3,677 runs, 1,056 came with sixes. That means 28.71 percent of Rohit’s runs were made by sending the ball into the air.
Due to the rain, the game was reduced to eight overs per side. India chose to bowl first after winning the toss. Australia posted 90/5 in their eight overs. Knocks from Aaron Finch (31 off 15 balls) and Matthew Wade (43* off 20) helped Australia put a challenging total on the board.
Axar Patel was the Indian bowlers’ choice and took 2/13 in two overs. Jasprit Bumrah also came into action again with a two-over spell of 1/23.
Team India chased 91 and got off to a great start, taking 39 in just 2.5 overs before sacking KL Rahul for 10 from 5 balls. Spinner Adam Zampa helped Australia make a short comeback by quickly trapping Virat Kohli (11 from 6 balls) and Suryakumar Yadav (golden duck), bringing India down to 55/3 in 4.3 overs.
But it was opener Rohit Sharma (46* on 20 balls) who kept one side stable and his partner Dinesh Karthik (10* on 2 balls) closed things off in style with a six and four in the first two balls of the final past. India finished in 92/4 in 7.2 overs.
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